RUPC 2016 Day2 H: Reflection Warp Machine
解法
それぞれの線を引いた時に行き来できる星たちを列挙しておく。後はどのワープを使うかをDPしていけば良い。
コード
#include <bits/stdc++.h> using namespace std; typedef long long ll; template <typename T> std::ostream& operator<<(std::ostream& out, const std::vector<T>& v) { if (!v.empty()) { out << '['; std::copy(v.begin(), v.end(), std::ostream_iterator<T>(out, ", ")); out << "\b\b]"; } return out; } template <class T, class U> void chmin(T& t, U f) { if (t > f) t = f; } template <class T, class U> void chmax(T& t, U f) { if (t < f) t = f; } struct UnionFind { vector<int> data; UnionFind(int size) : data(size, -1) {} UnionFind(const UnionFind& u) { data = u.data; } bool unionSet(int x, int y) { x = root(x); y = root(y); if (x != y) { if (data[y] < data[x]) swap(x, y); data[x] += data[y]; data[y] = x; } return x != y; } bool findSet(int x, int y) { return root(x) == root(y); } int root(int x) { return data[x] < 0 ? x : data[x] = root(data[x]); } int size(int x) { return -data[root(x)]; } }; int N; vector<int> x, y; map<pair<int, int>, vector<pair<int, int>>> m; void hoge(int i, int j) { //-2x(x2-x1)-2y(y2-y1)+()+() ll a = -2 * (x[j] - x[i]); ll b = -2 * (y[j] - y[i]); ll c = (x[j] * x[j] - x[i] * x[i]) + (y[j] * y[j] - y[i] * y[i]); for (int k = 0; k < N; ++k) { for (int l = k + 1; l < N; ++l) { if (abs(a * x[l] + b * y[l] + c) == abs(a * x[k] + b * y[k] + c) && (x[k] - x[l]) * (y[i] - y[j]) == (y[k] - y[l]) * (x[i] - x[j])) { m[{i, j}].push_back({k, l}); } } } } int main() { cin.tie(0); ios::sync_with_stdio(false); cin >> N; x.resize(N), y.resize(N); for (int i = 0; i < N; ++i) cin >> x[i] >> y[i]; for (int i = 0; i < N; ++i) { for (int j = i + 1; j < N; ++j) { hoge(i, j); } } UnionFind start(N); vector<pair<UnionFind, int>> dp; dp.push_back({start, 0}); int mi = N; for (int i = 0; i < N; ++i) { for (int j = i + 1; j < N; ++j) { vector<pair<UnionFind, int>> v; for (auto& p : dp) { if (p.first.findSet(i, j)) continue; UnionFind next(p.first); for (auto& q : m[{i, j}]) { next.unionSet(q.first, q.second); } for (int k = 1; k < N; ++k) { if (!next.findSet(0, k)) { v.push_back({next, p.second + 1}); break; } if (k == N - 1) chmin(mi, p.second + 1); } } for (auto& q : v) { dp.push_back(q); } } } cout << mi << endl; }